Java SquareRoot Application - Exercise

Modifying the SquareRoot application

Instructions

class SquareRoot2 {
  public static void main(String[] args) {
    try {
      double number = 
        Double.valueOf(args[0]).doubleValue();
      double root   = compute(number);
      System.out.println(
        "The square root of " + number +
        " is " + root);
    }
    catch (ArrayIndexOutOfBoundsException e) {
      System.out.println(
        "Please supply a command-line argument");
    }
    catch (NumberFormatException e) {
      System.out.println(
        "The command-line argument must be a number");
    }
  }

  static double compute(double number) {
    return Math.sqrt(number);
  }
}

1. Define a new exception called ImaginaryNumberException.
2. Add a throws clause to compute() that declares ImaginaryNumberException.
3. In compute, throw an instance of ImaginaryNumberException if number is less than 0.
4. In your main() method, catch ImaginaryNumberException and display a message.

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